Question

How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?

Answer 1

`n_(Cl^-)=25molCl^-`

Step-by-step explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

`5(molMgCl_2)/(L)`

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

`n_(Cl^-)=5(molMgCl_2)/(L)*(2molCl^-)/(1molMgCl_2) *2.5L\\\\n_(Cl^-)=25molCl^-`

Best regards.