Question

The perimeter of a rectangle is 48 in. If the length is twice

the width, what is the length of the rectangle?
A) 64 in.
B) 16 in.
C) 8 in.
D) 4 in.​

Answer 1

`\boxed{\sf Length \ of \ the \ rectangle = 16 \ in}`

Given:

Perimeter of rectangle = 48 in

Length = Twice the width

To Find:

Length of the rectangle

Explanation:

Let width of the rectangle be 'w'.

So,

Length of the rectangle = 2w

`\sf \implies Perimeter \ of \ rectangle = 2(Length + Width \\ \\ \sf \implies 48 = 2(2w + w) \\ \\ \sf \implies 48 = 2(3w) \\ \\ \sf \implies 48 = 6w \\ \\ \sf \implies 6w = 48 \\ \\ \sf \implies \frac{ \cancel{6}w}{ \cancel{6}} = (48)/(6) \\ \\ \sf \implies w = (48)/(6) \\ \\ \sf \implies w = \frac{8 * \cancel{6}}{ \cancel{6}} \\ \\ \sf \implies w = 8 \: in`

Width of the rectangle (w) = 8 in

Length of the rectangle = 2w

= 2 × 8

= 16 in