Question

Tony is opening a pizza restaurant and needs to determine the amounts of ingredients he will use in his pizzas. He wants the amount of dough for a medium pizza to be 3/2 times the amount of dough for a small pizza. And, he wants the amount of dough for a large pizza to be 5/2 times the amount of dough for a small pizza. Also, the amount of dough used for one large pizza should to be equal to the amount of dough used for one medium and one small pizza. So, he needs to determine how much dough to use for a small pizza. Use this information to complete the following tasks.

Answer 1

The equation for a small pizza is, 3/2s + s = 5/2s.

Next, to combine like terms the equation is, 5/2s = 5/2s.

After that, for opposite operations you write, 5/2s - 5/2s = 0.

When you combine the like terms for the last equation, you come up with,

0 = 0.

The small sized pizza does not have a specific size and is no longer part of the equation. Its' size can be anything, and the other sized pizzas will equal their equation towards the small pizza, still representing their same value.

Explanation:

cheese + sauce + dough + lots of meat + fire = happiness/pizza

(HopE ThIs HeLPs) ‍

Answer 2

If the amount of dough for a small pizza is S, for a large pizza is L and for a medium pizza is M, we have the equations:

M = (3/2)*S

L = (5/2)*S

L = M + S

First, we can convine the second and third equation and get:

(5/2)*S = M + S

and now we can replace M by the first equation:

(5/2)S = (3/2)*S + S = 5/2 S

so we have a trivial equation, S can be any number, this means that the system of equation is not well constructed.

For example, if S = 1Kg then:

M = (3/2)kg

L = (5/2)kg = (3/2)kg + 1 kg = 5/2kg