Answer:
Has infinite solutions
Step-by-step explanation:
-x + 5y = -3..... eq1
2x - 10y = 6 .... eq2
===============
make x the subject in equation 1
-x + 5y = -3
-x = -3 - 5y
x = 5y + 3
========= insert this in equation 2
2(5y + 3) - 10y = 6
10y + 6 -10y = 6
6 = 6
So, Has infinite solutions as L.H.S = R.H.S