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X= 3y-5

2x + 12y = -4
This is a system of equations can somebody solve it you can use any method ​

User Sundar
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2 Answers

6 votes
x=3y-5
2x+12y=-4

(-2)x=-6y+10
2x+12y=-4
12y=6
y=1/2

x=3y-5
2x+12y=-4

(-4)x=-12y+20
2x+12y=-4
-2x=16
x=-8
User Fizch
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3.4k points
3 votes

Answer:

x = -4, y = 1/3

Explanation:

=> x = 3y-5 (Equation 1)

=> 2x+12y = -4 (Equation 2)

Putting (1) in (2)

=> 2(3y-5)+12y = -4

=> 6y-10+12y = -4

=> 18y = -4+10

=> 18y = 6

Dividing both sides by 18

=> y = 6/18

=> y = 1/3

Putting y = 1/3 in Equation 1

=> x = 3(1/3)-5

=> x = 1-5

=> x = -4

User Jagge
by
3.6k points