Question

I NEED HELP PLEASE, THANKS! :)

A baseball player running forward at 3 meters per second throws a ball with a velocity of 20 meters per second at an angle of 20o with the horizontal. What is the resultant speed and direction of the throw? (Show work)

Answer 1

We are given that a baseball player is running forward at 3 meters per second, throwing a ball at an angle of 20 with respect to a velocity of 20 meters per second -

( Thus, the horizontal component should be 3 + 20( cos 20 ),

( Respectively the vertical component should be 20( sin 20 )

Horizontal Component = ( About ) 21.7938...

Vertical Component = ( About ) 6.8404....

Now the speed, or otherwise velocity can be calculated through the formula v^2 = ( v1 )^2 + ( v2 )^2 -

`v^2 = ( 21.8 )^2 + ( 6.84 )^2,\\v^2 = 475.24 + 46.7856,\\v^2 = ( About ) 522,\\v = 22.8 ( meters / second )\\\\Resultant Speed = 22.8 m / s`

And the direction can be calculated through the formula -
`direction = tan( v^2 / v^1 ),\\direction = tan( 6.84 / 21.8 ),\\direction = ( About ) 17.4 ( degrees )`

The resultant speed is 22.8 m / s, thrown with at an angle ( direction ) of 17.4 degrees