Answer:
Step-by-step explanation:
To find the [H3O+] of the solution, we can use the fact that HBr is a strong acid and completely dissociates in water. Therefore, the concentration of H3O+ is equal to the molar concentration of HBr:
[H3O+] = 0.0085 M
To find the [OH-], we can use the equation:
Kw = [H3O+][OH-]
Where Kw is the ion product constant for water, which has a value of 1.0 x 10^-14 at 25°C.
Rearranging the equation to solve for [OH-], we get:
[OH-] = Kw / [H3O+]
[OH-] = (1.0 x 10^-14) / (0.0085)
[OH-] = 1.176 x 10^-12 M
To find the pH of the solution, we can use the equation:
pH = -log[H3O+]
pH = -log(0.0085)
pH = 2.07
Therefore, the [H3O+] of the solution is 0.0085 M, the [OH-] is 1.176 x 10^-12 M, and the pH is 2.07.