Question

Ohm's Law for electrical circuits is stated Vequals​RI, where V is a constant​ voltage, R is the resistance in ohms and I is the current in amperes. Your firm has been asked to supply the resistors for a circuit in which V will be 9 volts and I is to be 5 plus or minus 0.1 amperes. In what interval does R have to lie for I to be within 0.1 amps of the target value Upper I 0 equals 5 question mark

Answer 1

The resistance interval is
`R = 1.8 \pm 0.037`

Step-by-step explanation:

From the question we are told that

The voltage is V = 9 V

The current is
`I = 5 \pm 0.1`

The maximum current would be

`I_(max) = 5 + 0.1 = 5.1 \ A`

The minimum current would be

`I_(min) = 5 - 0.1 = 4.9 \ A`

The maximum resistance is

`R_max = (V)/(I_(min))`

`R_max = (9)/(4.9)`

`R_max = 1.837 \Omega`

The minimum resistance is

`R_(min) = (V)/(I_(max))`

`R_(min) = (9)/(5.1)`

`R_(min) = 1.765 \Omega`

and
`R = (9)/(5) = 1.8 \Omega`

The interval R lies is

`R = 1.8 \pm 0.037`