Question

A rotating wheel requires 3.08-s to rotate through 37.0 revolutions. Its angular speed at the end of the 3.08-s interval is 97.4 rad/s. What is the constant angular acceleration of the wheel?

Answer 1

31.62
`rad/s^2`

Step-by-step explanation:

The angular velocity of the wheel at the end of the interval is 97.4 rad/s.

The time taken is 3.08 s.

Angular acceleration is given as:

`a = \omega / t`

where ω = angular velocity

t = time

Therefore, angular acceleration is:

a = 97.4 / 3.08

a = 31.62
`rad/s^2`