Answer: The lowest possible melting point for engine coolant that is 26.1% ethylene glycol is

Step-by-step explanation:
Depression in freezing point or melting point is given by:

= Depression in freezing point
i= vant hoff factor = ( 1 for non electrolyte)
= freezing point constant for water=

m= molality

Given : 26.1 g of ethylene glycol in 100 g of water
Weight of solvent (water)= 100 g = 0.1 kg (1kg=1000g)
Molar mass of solute (ethylene glycol) = 62 g/mol
Mass of solute (ethylene glycol) added = 26.1 g



Thus the lowest possible melting point for engine coolant that is 26.1% ethylene glycol is
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