Question

Besides the gravitational force, a 2.80-kg object is subjected to one other constant force. The objectstarts from rest and in 1.20 s experiences a displacement of (4.20 i - 3.30 j) m, where the direction of jis the upward vertical direction. Determine the other force.

Answer 1

The other force acting on the object is -7.70 N in the upward vertical direction.

Step-by-step explanation:

To determine the other force acting on the object, we need to analyze the given information. The displacement of the object is (4.20i - 3.30j) m. We know that the object starts from rest, so its initial velocity is zero. Using the formula for displacement, velocity, and time, we can find the acceleration of the object in the j-direction. The other force acting on the object can then be calculated using the formula F = ma, where 'm' is the mass of the object and 'a' is the acceleration.

Calculation:

Initial velocity (v0) = 0 m/s

Displacement (Δx) = 4.20 m (in the i-direction)

Time (t) = 1.20 s

Acceleration (aj) = (Δvj) / t = (-3.30 m/s - 0 m/s) / 1.20 s = -2.75 m/s²

Mass of the object (m) = 2.80 kg

Other force (Fother) = m * aj = 2.80 kg * (-2.75 m/s²) = -7.70 N

Therefore, the other force acting on the object is -7.70 N in the upward vertical direction.