Question

Choose the equation that represents the line that passes through the point (2,6) and has a slope of -5.

Oy = -5x + 2
Oy = -5x - 6
Oy = -5x - 4
Oy = -5x + 16

Answer 1

y = -5x + 16

Explanation:

Equation of line in slope intercept form is

y = mx + c where

m = slope of line and c is y intercept.

Given that slope of line is -5

hence we can use m = -5 then

equation of line will be y = -5x + c

this line passes though (2,6), hence

we put y = 6 and x = 2 in the equation y = -5x + c, to find c

y = -5x + c

=> 6 = -5*2 + c

=> 6 = -10 + c

=> c = 6+10 = 16

Thus, equation of line is y = -5x + 16 (i.e fourth option)