Answer:
Explanation:
In Δ ABC & ΔADC
AC bisect ∠BCD given
∠ACB ≅ ∠ACB AC bisect ∠BCD
DC ⊥ AD Given
BC ⊥ AB Given
∠ABC = ∠ADC Right angles are ≅
AC ≅ AC Common to both triangle ΔABC & ΔADC
ΔABC ≅ ΔADC AAS congruent
BC ≅ DC CPCT
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