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If there are 16 signal combinations (states) and a baud rate (number of signals/second) of 8000/second, how many bps could I send

User Nehem
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1 Answer

7 votes

Answer:

32000 bits/seconds

Step-by-step explanation:

Given that :

there are 16 signal combinations (states) = 2⁴

bits n = 4

and a baud rate (number of signals/second) = 8000/second

Therefore; the number of bits per seconds can be calculated as follows:

Number of bits per seconds = bits n × number of signal per seconds

Number of bits per seconds = 4 × 8000/second

Number of bits per seconds = 32000 bits/seconds

User Reza Heydari
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