Question

PLEASE ANSWER!!! You are helping wish some repairs at home. you drop a hammer and it hits the floor at a speed of 12 feet per second. If the acceleration due to gravity (g) is 32 feet/second², how far above the ground (h) was the hammer when you dropped it? Use the formula: v=√2gh A. 2.25 feet B. 18.0 feet C. 8.5 feet D. 1.0 foot

Answer 1

h = 2.25 m

Explanation:

Given:

Speed = v = 12 ft/sec

Acceleration due to gravity = g = 32 ft/sec²

Required:

Height = h = ?

Formula:

v =
`√(2gh)`

Solution:

For h, the formula will be:

=> h =
`(v^2)/(2g)`

=> h =
`((12)^2)/(2(32))`

=> h =
`(144)/(64)`

=> h = 2.25 m