Question

an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object be two thirds of the kinetic energy?

Answer 1

333.3 m

Step-by-step explanation:

Given

`m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2`

Potential energy =
`(2)/(3)\ of\ Kinetic\ energy`......Equation(1)

We know that

Potential energy=mgh

Kinetic energy =
`(1)/(2) mv^(2)`

Now From the Equation(1)

`mgh=(2)/(3)*(1)/(2) mv^(2)\\ gh=(v^(2) )/(3) \\10 * h=\ (10000)/(3)\\ h=\ (1000)/(3) \\h=333.3\ m`