Answer:
The average speed on this trip was 46.15 mph. The correct option is A.
Explanation:
In order to calculate the average speed, we need to apply the following formula:
![v_(avg) = \frac{\text{distance}}{\text{time}}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3vtum89gkybuz115687fkekij58lrul01v.png)
We were given the distance between the two cities in miles, therefore we can directly apply it to the expression. Although the time was given in the hh:mm 12 h format and we need a diference in hours, so we will convert that as shown below:
![\text{time departure} = 9 + (50)/(60) = 9.83 \text{ h}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yer114fxs0hboljza9jngc65uv0p3bfj48.png)
![\text{time arrival} = 12 + 5 + (30)/(60) = 17.5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u80lc9e9fwqf2bpfcjmiee14b7athfc826.png)
The elapsed time of the trip is the difference between these:
![\text{time} = 17.5 - 9.83 = 7.67 \text{ h}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2bbuciar9ifzg3kwuvosivljpv4w53wqe2.png)
We can now apply it to the formula:
![v_(avg) = (354)/(7.67) = 46.15 \text{ mph}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ck4lb6lsj3vtdgcfog4upvrkg78fykzloi.png)
The average speed on this trip was 46.15 mph. The correct option is A.