Answer:
p-value = 0.8572
The current sample results do not show that bullish sentiment differs from its long-term average of 0.39, that is, the sample results show that there is no difference between the current bullish sentiments and the long-term average of 0.39.
Explanation:
For hypothesis testing, the first thing to define is the null and alternative hypothesis.
The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.
While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.
For this question, we want to test if the current sample results show that bullish sentiment differs from its long-term average of 0.39.
The null hypothesis would be that there isn't enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.
The alternative hypothesis is that there is enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.
Mathematically, if the population proportion of bullish members for that period/week is p.
The null hypothesis is represented as
H₀: p = 0.39
The alternative hypothesis is represented as
Hₐ: p ≠ 0.39
To do this test, we will use the z-distribution because although, no information on the population standard deviation is known, 5he sample size is large enough for the sample properties to approximate the population properties.
So, we compute the z-test statistic
z = (x - μ)/σₓ
x = sample proportion of bullish members = 0.385
μ = p₀ = the standard we are comparing against = 0.39
σₓ = standard error = √[p(1-p)/n]
where n = Sample size = 300
σₓ = √[0.385×0.615/300] = 0.0280935936 = 0.02809
z = (0.385 - 0.39) ÷ 0.02809
z = -0.1779765192 = -0.18
checking the tables for the p-value of this z-statistic
Significance level = 0.05
The hypothesis test uses a two-tailed condition because we're testing in both directions.
p-value (for t = 0.18, at 0.05 significance level, with a two tailed condition) = 0.857153
The interpretation of p-values is that
When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.
So, for this question, significance level = 0.05
p-value = 0.857153
0.857153 > 0.05
Hence,
p-value > significance level
This means that we fail to reject the null hypothesis & say that there isn't enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.
Hope this Helps!!!