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Marvin and Ruby had the same number of stickers. After Marvin gave 12 stickers to Ruby, Ruby had 4 times as many as Marvin. How many stickers did Ruby have in the beginning?

User Dacker
by
4.8k points

1 Answer

5 votes

Answer:

20 Tickets

Explanation:

Given

Marvin and Ruby had the same number of stickers.

Let

no. of tickets with Ruby = No. of tickets with Marvin = x

condition

Marvin gave 12 ticket to Ruby

Now\

no. of tickets with Ruby = x+12

No. of tickets with Marvin = x-12

Ruby had 4 times as many as Marvin

Thus,

no. of tickets with Ruby = 4* No. of tickets with Marvin

x+12= 4(x-12) = 4x-48

x+12 = 4x-48

adding 48 both sides

x+12 +48= 4x-48+48

x+60 = 4x

subtracting 4 from both sides

x+60 -x= 4x -x

60 = 3x

dividing both side by 3

60/3 = 3x/3

x = 20

Thus, Ruby had 20 tickets in the beginning.

User Farhad Bagherlo
by
5.2k points
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