Question

The given line passes through the points and (4,1).

On a coordinate plane, a line goes through (negative 4, negative 3) and (4,1).
What is the equation, in point-slope form, of the line that is perpendicular to
the given line and passes through the point (-4, 3)?​

Answer 1

y-3 = -2(x+4)

Explanation:

Answer 2

Hey there! :)

Answer:

y -3 = -2(x + 4).

Explanation:

Begin by calculating the slope of the line shown in the graph. Use the slope formula:

`m = \frac{\text{rise}}{\text{run}} = (y_2 - y_1)/(x_2 - x_1)`

Plug in two coordinates:

`m = (1-(-3))/(4-(-4))`

Simplify:

`m = (4)/(8)`

`m = (1)/(2)`

Therefore, the slope of the line is 1/2.

A line that is perpendicular contains a slope that is the negative reciprocal. Therefore:

1/2 --> -2.

Plug the slope into the point-slope formula:

y -3 = -2(x + 4). This is your equation in point-slope form!