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Identify the axis of symmetry of the given quadratic y= -3x^2 - 12
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2 votes
Identify the axis of symmetry of the given quadratic
y= -3x^2 - 12

User Skoz
by
5.6k points

1 Answer

5 votes

Answer:


(d)/(dy)(-3x^(2) -12) = -6x

0 = -6x

0 = x


-3(0)^(2) -12 = -12

(0,-12)

Explanation:

User Abhinav Ramakrishnan
by
4.6k points
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