Question

What is an equivalent equation solved for yz?

The slope, m, of a linear equation can be found using the
formula m = V2-V, where the x- and y-values come from
X2 - X2
two ordered pairs, and (x1, y1) and (x2, y2).
y2 = mx2 - X1 + 71
Y2 = mx2 - X1 - 1
y2 = m(x2 -- X1) + Y1
y2 = m(x2 - X1) - Y1

Answer 1

(C)
`y_2=m(x_2-x_1)+y_1`

Explanation:

The slope, m, of a linear equation can be found using the formula

`m=(y_2-y_1)/(x_2-x_1)`

We want to solve for
`y_2`.

First, we cross multiply,

`m=(y_2-y_1)/(x_2-x_1)\\y_2-y_1=m(x_2-x_1)\\$Add y_1$ to both sides\\y_2=m(x_2-x_1)+y_1`

The correct option is C.