Answer:
1.148×10^6 N
Step-by-step explanation:
The kinetic energy of the train is ...
KE = (1/2)mv^2 = (1/2)(3.6×10^5 kg)(115 km/h × (1000 m/km)/(3600 s/h))^2
≈ 1.83681×10^8 J
This is the work required to stop the train, so is ...
F·d = KE
F = KE/d = (1.83681×10^8 J)/(160 m) = 1.148×10^6 N
The force required to stop the train is 1.148×10^6 newtons.