Answer:
(a) p
(b) the probability does not change at all
Explanation:
(a) Let A and B be the jurors with probability 'p' of making the correct decision, and C be the juror that doesn't care. The case will be correctly decided if any of the following combinations of jurors decide the case correctly:
AB, AC, BC, ABC.
The probability of one of those outcomes occurring is:
![P=(p*p*0.5)+(p*(1-p)*0.5)+(p*(1-p)*0.5)+(p*p*0.5)\\P=p^2+p-p^2\\P=p](https://img.qammunity.org/2021/formulas/mathematics/college/573bcx9ds6lkllh5sasdix0u5w9v6m4xdc.png)
The probability is p.
(b) If two of the juros quit, the probability of correctly deciding the case lies on just one juror that correctly decides with probability 'p'. Therefore, the probability of deciding the case does not change at all