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What is the product of (3y^-4) (2y^-4) A. 6/y^8 B. 1/6y^8 C. 6/y^16 D. 1/6y^16

1 Answer

2 votes

Answer:

A

Explanation:

We want to simplify the product
(3y^(-4))(2y^(-4)).

First, notice that both terms have a power with base y, so by the properties of exponents, we can combine the two
y^(-4) into one by adding their exponents:


y^(-4)*y^(-4)=y^(-4+(-4))=y^(-8)

Now, let's multiply the 3 and 2:

3 * 2 = 6

So far, we have
6y^(-8). However, we have a negative exponent that we want to make positive. Remember another property of exponents that when we have a negative exponent, we can make it positive by taking the reciprocal of it. Thus,
y^(-8) becomes
(1)/(y^8).

Hence, our answer is
6*(1)/(y^8)=(6)/(y^8), or A.

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