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I NEED HELP PLEASE HURRY, THANKS! :)

I NEED HELP PLEASE HURRY, THANKS! :)-example-1
User Punnerud
by
3.5k points

2 Answers

3 votes

Answer:

B

using SOHCAHTOA

COS THETA WILL BE EQUALS TO ROOT 5/3 AND TAN THETA WILL BE EQUALS TO 2ROOT 5/3

User Pmdj
by
3.6k points
5 votes

Answer:

B.

Explanation:

First, note that since
sin(\theta)=2/3, this means that the opposite side is 2, the hypotenuse is 3, and the last, adjacent side is
\sqrt{5\\.

Also note that we are told that
sec(\theta)<0. This means that
\theta cannot be in quadrants 1 nor 4 because (remember All Students Take Calculus?) in those quadrants cosine and secant are positive. Also, we know that sine is positive so we can conclude that
\theta is in the second quadrant.

In the second quadrant, sine is positive, cosine is negative, and tangent is negative. Now we can answer the question. We already know the side lengths: opposite=2, adjacent=
-√(5) (because it's in Quadrant II), and hypotenuse=3.

Therefore...


cos(\theta)=-√(5) /3


tan(\theta)=2/(-√(5))=-(2√(5)/5)

User Moho
by
3.4k points