Question

2. What is the equation of a line parallel to y = -5x + 3 that passes through (3, 1)?

Answer 1

Explanation:

line parallel to given line has same slope i.e.,-5

eq. of line through (3,1) with slope -5 is

y-1=-5(x-3)

y-1=-5x+15

y=-5x+15+1

or y=-5x+16

Answer 2

Equation of a line is y = mx + c

where

m = gradient

c = y intercept

y = -5x + 3

Comparing this equation with the above formula

m = - 5

Since the lines are parallel their gradients are also the same.

So gradient of the parallel line is also 5

That's m = -5

Equation of the parallel line using point

(3, 1) and gradient m = -5 is

y - 1 = -5(x - 3)

y - 1 = -5x + 15

y = -5x + 15 + 1

Final answer is

y = -5x + 16

Hope this helps.