Question

A physicist wants to study the motion of a car.

a. The physicist measures how long it takes a car to go 50 miles. How many
kilometers is this? (Note: 1 mi = 1.61 km)

b. In another experiment, the car travels 22.3 miles. How many yards is this?
(Note: 1 mi = 5280 ft; 1 yd = 3 ft)

Answer 1

a.

Step-by-step explanation:

in a

`1 mi = 1.61km`

so,in 50 miles

`50 mi = 50 * 1.61`

`= 80.5 \: km`

in b

`1 \: mi = 1760 \: yd`

so in 22.3 miles

`22.3 = 22.3 * 1760`

`= 39248 \: yd`