Question

The function h(x)=12/x-1 is one to one. Algebraically find it’s inverse, h^-1(x).

Answer 1

Explanation:

hello,

I assume that you mean

`h(x)=(12)/(x-1)`

so first of all let's take x real different from 1 , as this is not allowed to divide by 0

`(hoh^(-1))(x)=x=h(h^(-1)(x))=(12)/(h^(-1)(x)-1) \ \ \ so\\h^(-1)(x)-1=(12)/(x) \\\\h^(-1)(x)=1+(12)/(x)`

and this is defined for x real different from 0

hope this helps