Question

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solution using 100 mL of ethyl acetate per extraction if the partition coefficient is 8

Answer 1

The grams of material lost in the aqueous phase after two extractions using ethyl acetate can be calculated by multiplying the initial amount of material by the partition coefficient. In this case, the initial amount is 5 grams and the partition coefficient is 8, resulting in a final amount of 40 grams.

Step-by-step explanation:

To calculate the grams of material lost in the aqueous phase, we first need to determine the amount of material in the solution before and after extraction. The initial amount of material in the solution is 5% of 100 mL, which is 5 grams. Since two extractions are carried out, a total of 200 mL of ethyl acetate is used. To calculate the final amount of material in the aqueous phase, we multiply the initial amount by the partition coefficient, which is 8. Therefore, the final amount of material in the aqueous phase is 5 grams x 8 = 40 grams.