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Could someone please help me with this: Solution set of lx^2+mx+n=0 is?

User Bjornicus
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1 Answer

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Answer:

Quadratic equations have the solution

x = [-b +-sqr root(b^2 -4ac)] / 2a

In the given equation a = l; b = m and c = n So,

x = [-m +-sqr root(m^2 -4*l*n)] / 2*l

Explanation:

User Nxtwrld
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