Question

A certain organ pipe, open at both ends, produces a fundamental frequency of 272 HzHz in air. Part A If the pipe is filled with helium at the same temperature, what fundamental frequency fHefHef_He will it produce? Take the molar mass of air to be 28.8 g/molg/mol and the molar mass of helium to be 4.00 g/molg/mol .

Answer 1

To find the fundamental frequency of the organ pipe filled with helium, you can use the formula f_He = f_Air * √(m_Air/m_He), where f_Air is the fundamental frequency of the pipe in air, m_Air is the molar mass of air, and m_He is the molar mass of helium. Given the values provided, the fundamental frequency of the pipe filled with helium is 816 Hz.

Step-by-step explanation:

To find the fundamental frequency of the organ pipe filled with helium, we can use the formula:

fHe = fAir * √mAir/mHe

where fAir is the fundamental frequency of the pipe in air, mAir is the molar mass of air, and mHe is the molar mass of helium.

Given that fAir = 272 Hz, mAir = 28.8 g/mol, and mHe = 4.00 g/mol, we can calculate the fundamental frequency of the pipe filled with helium:

fHe = 272 Hz * √(28.8 g/mol)/(4.00 g/mol) = 816 Hz.