Question

9. If y = kx, where k is a constant, and y = -3

when x = 6, what is the value of x when y = 12?

Answer 1

x would be -24

Explanation:

since k is a constant, we have to find out what k is from the equation

. -3=6(k) divide both sides by 6 to get that k is -0.5/-1/2.

then, solve for what x is when y is 12 by setting up the equation 12=(-0.5)x. this would result in x being -24

Answer 2

Hey there! :)

Answer:

x = -24.

Explanation:

Plug in the values to find the value of 'k':

-3 = k(6)

Divide both sides by 6 to solve for 'k':

-3/6 = k

k = -1/2

Plug this into the equation to solve for the value of x when y= 12:

12 = -1/2(x)

Divide both sides by -1/2:

-24 = x

x = -24.