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To determine whether the mutations in the seven strains leading to the wingless phenotype are in the same gene, your lab sets up complementation tests. You obtain the following results ("+" indicates that complementation was observed; "-" indicates that no complementation was observed).

mutation 1 2 3 4 5 6 7
1 -
2 - -
3 + + -
4 - - + -
5 + + - + -
6 + + - + - -
7 - - + - + + -

User Macksol
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1 Answer

4 votes

The question is incomplete as it lacks the question and has only information regarding the question. however, the correct question is as follows :

How many different genes are contributing to the wingless phenotypes in these mutant fly strains?

Answer:

The correct answer is - Two genes.

Step-by-step explanation:

In the given question there are two mutation groups based on the given seven results:

1st group :

Mutations 1, complement with 2,4, and 7 and also complement each other, thus, are on the same gene.

2nd group:

Mutations 3, 5, and 6 did not complement each other but complemented with mutations 1, 2, 4, and 7. Thus, these three mutations are present together on a different gene.

User Jcjr
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5.1k points