Answer:
The new volume is 81.2% of the prior, this is true for any for any values of radius and height, as long as they are changed as stated.
Explanation:
The volume of a cylinder is given by:
![V = \pi*r^2*h](https://img.qammunity.org/2021/formulas/mathematics/high-school/eknnilod70s58af2nodgqzusrjqh8r2jsn.png)
If we increase the diameter by 15%, then the radius is increased by 7.5% and the new radius is:
![r_(new) = 1.075*r](https://img.qammunity.org/2021/formulas/mathematics/high-school/egu8kxo177imq8cca5mjs7od7ohzx0oe7k.png)
If we decrease the height by 30%, then the new height is 70% of the prior and is given by:
![h_(new) = 0.7*h](https://img.qammunity.org/2021/formulas/mathematics/high-school/q96juq16b5tzxizsly7l658htxlrg4gcz6.png)
Applying to the volume formula we have:
![V_(new) = pi*(r_(new))^2*h_(new)](https://img.qammunity.org/2021/formulas/mathematics/high-school/kibsv0wapzngjhojawbttkekxzlfiy9krq.png)
![V_(new) = \pi*(1.075*r)^2*0.7*h\\V_(new) = 1.16*0.7*\pi*r^2*h\\V_(new) = 0.812*\pi*r^2*h\\V_(new) = 0.812*V](https://img.qammunity.org/2021/formulas/mathematics/high-school/8es2r6nxqr3zmr5fueksnm2vlioay8bldo.png)
The new volume is 81.2% of the prior, this is true for any for any values of radius and height, as long as they are changed as stated.