Answer:
a) 8.33 x
Pa or 8.22 x
atm
b) 1.66 x
Pa or 1.63 x
atm
c) 2.77 x
kg/m^2-s
Step-by-step explanation:
Intensity of light = 2500 W/m^2
area = 25 ft^2
a) average radiation pressure on a totally absorbing section of the floor
![Pav = (I)/(c)](https://img.qammunity.org/2021/formulas/physics/college/hnxuy8qdtqnox7jtfltuv72tv7j9n9f5j9.png)
where I is the intensity of the light
c is the speed of light =
![3*10^(8) m/s](https://img.qammunity.org/2021/formulas/physics/college/flv5jw1b761hp88t0n774bgt0bsd6edc6x.png)
= 8.33 x
Pa
1 pa =
![9.87*10^(-6)](https://img.qammunity.org/2021/formulas/physics/college/e0uto864gvyg61itt1u742x488nd45jm3n.png)
8.33 x
Pa = 8.22 x
atm
b) average radiation for a totally radiating section of the floor
![Pav = (2I)/(c)](https://img.qammunity.org/2021/formulas/physics/college/dk4usqvut062clrhbulqk2fz40tldax6rq.png)
this means that the pressure for a totally radiating section is twice the average pressure of the totally absorbing section
therefore,
Pav = 2 x 8.33 x
= 1.66 x
Pa
or
Pav in atm = 2 x 8.22 x
= 1.63 x
atm
c) average momentum per unit volume is
![m = (I)/(c^(2) )](https://img.qammunity.org/2021/formulas/physics/college/3c6pcgl4uu54n6m2ktcqml4mtn3e0v5tqh.png)
= 2.77 x
kg/m^2-s