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In the 25 ftft Space Simulator facility at NASA's Jet Propulsion Laboratory, a bank of overhead arc lamps can produce light of intensity 2500 W/m^2 at the floor of the facility. (This simulates the intensity of sunlight near the planet Venus.)

Required:
Find the average radiation pressure (in pascals and in atmospheres) on

a. A totally absorbing section of the floor.
b. A totally reflecting section of the floor.
c. Find the average momentum density (momentum per unit volume) in the light at the floor.

User Alonzorz
by
3.5k points

1 Answer

7 votes

Answer:

a) 8.33 x
10^(-6) Pa or 8.22 x
10^(-11) atm

b) 1.66 x
10^(-5) Pa or 1.63 x
10^(-10) atm

c) 2.77 x
10^(-14) kg/m^2-s

Step-by-step explanation:

Intensity of light = 2500 W/m^2

area = 25 ft^2

a) average radiation pressure on a totally absorbing section of the floor
Pav = (I)/(c)

where I is the intensity of the light

c is the speed of light =
3*10^(8) m/s


Pav = (2500)/(3*10^(8) ) = 8.33 x
10^(-6) Pa

1 pa =
9.87*10^(-6)

8.33 x
10^(-6) Pa = 8.22 x
10^(-11) atm

b) average radiation for a totally radiating section of the floor


Pav = (2I)/(c)

this means that the pressure for a totally radiating section is twice the average pressure of the totally absorbing section

therefore,

Pav = 2 x 8.33 x
10^(-6) = 1.66 x
10^(-5) Pa

or

Pav in atm = 2 x 8.22 x
10^(-11) = 1.63 x
10^(-10) atm

c) average momentum per unit volume is


m = (I)/(c^(2) )


m = (2500)/((3*10^(8)) ^(2) ) = 2.77 x
10^(-14) kg/m^2-s

User Vetri
by
3.7k points