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What are the zeros of the polynomial function

F(x) = x^3 - 5x^2 - 6x?
A. X= -2, x = 0, and x = 3
B. x = -1, x = 0, and x = 6
C. x = -3, x = 0, and x = 2
D. x = -6, x = 0, and x = 1

1 Answer

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Answer:

B

Explanation:

F(x) = x^3 - 5x^2 - 6x

F(x)=x(x^2-5x-6)

F(x)=x(x-6)(x+1)

So, x=0,-1,6

User Maxime Rouiller
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