Question

What is the equation of the line that isPerpendicular to y=1/5×+4 and thar passes through (5,-4)?

Answer 1

Equation of a line is y = mx + c

m = slope

c = intercept on y axis

y=1/5×+4

Comparing with the above equation

Slope = 1/5

Since the lines are perpendicular to each other the slope of the line we are to find is the negative inverse of the original equation.

Slope = -5

Equation of the line using point

(5 , -4)

y + 4 = -5( x - 5)

y + 4 = -5x + 25

y = -5x + 21

Hope this helps

Answer 2

y = -5x + 21

Explanation:

Step 1: Find the slope

Take the negative reciprocal of the original equation

y = -5x + b

Step 2: Find b using given coordinate

-4 = -5(5) + b

-4 = -25 + b

b = 21

Step 3: Write equation

y = -5x + 21

And we have your equation!