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The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 1,000 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.

User Vizjerei
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2 Answers

7 votes

Answer: it’s B on edge

Explanation:

User Smellyarmpits
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7.6k points
5 votes

Answer:

3.0

Explanation:

The magnitude of an earthquake is given as:


M = log_(10)(I)/(S)

where I = intensity of earthquake

S = intensity of standard earth quake

When the intensity of the earthquake is 1000 times the intensity of a standard earth, that means that:

I = 1000S

Therefore:


M = log_(10)(1000S)/(S) \\\\M = log_(10)1000\\\\M = 3.0

The magnitude is 3.0

User Guylhem
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