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When [(a2bc4)(ab3c2)]2(b2c5)3 is simplified, the exponent of b is Answer

all the numbers are roots and powers

User ErnestoE
by
8.1k points

1 Answer

1 vote

Answer:

14

Explanation:

We want to simplify
[(a^2bc^4)(ab^3c^2)]^2 (b^2c^5)^3 so as to find the exponent of b.

Let us expand all brackets:


[(a^2bc^4)(ab^3c^2)]^2 (b^2c^5)^3\\\\= [a^3b^4c^6]^2 (b^(2*3)c^(5*3))\\\\= [a^6b^8c^(12)] (b^(6)c^(15))\\\\= a^6b^(8+6)c^(12 + 15)\\\\= a^6b^(14)c^(27)

The exponent of b is 14.

User Unii
by
8.2k points

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