Question

- find the general term of the sequence 1,-1,1-1​

Answer 1

The general term of the sequence is

`{ - 1}^(n - 1)`

Explanation:

The sequence above is a geometric sequence

For an nth term in a geometric sequence

`u(n) = a(r) ^(n - 1)`

Where n is the number of terms

a is the first term

r is the common ratio

From the above sequence

a = 1

r = -1/1 = -1

The nth term of the sequence is

`u(n) = 1 ({ - 1})^(n - 1) \\ = { - 1}^(n - 1)`

Hope this helps you