Answer:
∑(i+1)³,i=1→n-1
Explanation:
8=2³=(1+1)³
27=3³=(2+1)³
64=4³=(3+1)³
125=5³=(4+1)³
........................
n³=(n-1+1)³
∑ (i+1)³,i=1→n-1
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