Answer: 24950
Explanation:
We use the formula
sn=n2(2a+(n−1)d)
To find the sum of the first n terms of an arithmetic series with common difference d (5) and first term a (2).
Sn=100/2(2*2+(100−1)5)
Solving for a we obtain:
Sn=50(4+495)
Sn=50(499) = 24950