Answer:
![\boxed{\sf \ the \ solutions \ are \ -5 \ and \ -4/3 \ }](https://img.qammunity.org/2021/formulas/mathematics/college/i32ypjov6247twmg1g0f87mmll18hzrpr1.png)
Explanation:
Hello,
we need to find x so that
|2x-1|=|4x+9|
and we know that |x|=x if x >= 0 -x otherwise
2x-1=0 <=> 2x=1 <=> x = 1/2
4x+9=0 <=> 4x=-9 <=> x = -9/4
So we need to work in three different intervals
case 1: x <= -9/4 ( <= 1/2)
so |2x-1| = -(2x-1) = -2x+1
and |4x+9| = -4x-9
so we need to solve -2x+1=-4x-9<=> 2x=-9-1=-10 <=> x = -5
case 2: -9/4 <= x <= 1/2
so |2x-1| = -(2x-1) = -2x+1
and |4x+9| = 4x+9
so we need to solve -2x+1=4x+9<=> 6x=1-9=-8 <=> x = -8/6 = -4/3
case 3: -9/4 <= 1/2 <= x
so |2x-1| = 2x-1
and |4x+9| = 4x+9
so we need to solve 2x-1=4x+9<=> 2x=-1-9=-10 <=> x = -10/2 = -5
Finally, the solutions are -5 and -4/3
to verify, you can see below the graph of the two functions