Answer:
y-6x = 9
Explanation:
The question is incomplete. Here is the complete answer.
A given line has the equation 2x + 12y = −1.
What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?
General formula of equation of a line is exspressed as y = mx+c
m = gradient or slope
c = intercept
Step 1: we need to first get the slope of the given equation of a line by rewriting the equation in standard form y = mx+c
2x + 12y = −1
12y = -1-2x
y = -1/12-2x/12
y = -1/6 x - 1/12
From the equation above, it can be seen that the slope (m) of tghe line is -1/6.
Since both lines are perpendicular, the slope of the unknown line will be;
M = -1/m
M = -1/(-1/6)
M = 6
Step 2: We will find the intercept c by substituting the point (0,9) and the slope into the equation y = mx+c
9 = 6(0)+ c
c = 9
Stwp 3: We will find the equation of the line perpendicular to the given line by substituting the value of m and c into the equation y = mx+c
y = 6x+9
y-6x = 9
The equation in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9) is y-6x = 9