Answer:
The message is S E C R E T A G E N T M A N
Explanation:
This is a very easy exercise, follow the steps taken below:
Step 1: Find

![A = \left[\begin{array}{ccc}1&2\\1&3\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/iu7bm19e02rt2v28euw04xnq70nh80z3hq.png)
Note that If
![M = \left[\begin{array}{ccc}a&b\\c&d\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/c9duahy8bucyv7yo9q82g1wuyro34z8cs8.png)
then
![M^(-1) = \left[\begin{array}{ccc}a&-b\\-c&a\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/mrjauysoonemjiy1ryjw8smlw9c1cvxtuy.png)
Therefore,
![A^(-1) = \left[\begin{array}{ccc}3&-2\\-1&1\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/ccqs8azol2uklo59b7lcnlinhq43z7syn0.png)
Step 2: Find A⁻¹B ( i.e product of A and B)
![B = \left[\begin{array}{cccccccc}29&39&45&2&17&54&26&29\\34&57&65&3&22&74&39&43\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/bdxi2kgj1olrwtswlzcdw2ef5c2sfm1zdb.png)
![A^(-1) B = \left[\begin{array}{ccc}3&-2\\-1&1\end{array}\right] \left[\begin{array}{cccccccc}29&39&45&2&17&54&26&29\\34&57&65&3&22&74&39&43\end{array}\right]]()
![A^(-1)B = \left[\begin{array}{cccccccc}19&3&5&0&7&14&0&1\\5&18&20&1&5&20&13&14\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/1074b8upha9rfa5g6kr9ga053vn01i2taa.png)
Step 3: Decode the message in the matrix above
The message will be decoded in this order:
Note that 0 stands for empty space
19 5 3 18 5 20 0 1 7 5 14 20 0 13 1 14
S E C R E T A G E N T M A N
The message encoded is: S E C R E T A G E N T M A N