Answer:
16.10 kJ
Step-by-step explanation:
The thermal energy created in the slope can be found by definition of work (W):
![W = E_(f) - E_(i) = K_(f) + P_(f) + Th_(f) - (K_(i) + Th_(i))](https://img.qammunity.org/2021/formulas/physics/college/ifbotpok28cwhylxnsp2doqu7ekwfnols6.png)
Where:
and
: is the final and initial kinetic energy
: is the final potential energy
and
: is the final and initial thermal energy
![W = (1)/(2)mv_(f)^(2) + mgh - (1)/(2)mv_(i)^(2) + Th_(f) - Th_(i)](https://img.qammunity.org/2021/formulas/physics/college/qsh8j5tndnak3t6mem95in097btm34ocej.png)
We have that W is:
Where:
F: is the force equal to the tension (T)
d: is the displacement = 120 m
And since the speed is constant,
=
we have:
![T*d = mgh + \Delta Th](https://img.qammunity.org/2021/formulas/physics/college/lgwbxl7ce87qcefwbgsy28bdachbqqfo9z.png)
Therefore, the thermal energy created in the slope and the tube during the ascent is 16.10 kJ.
I hope it helps you!