Answer:
Anle at B
b = 56.25°
Explanation:
Triangle ABC is a right angle triangle. we are required to look for the angle at B
To do that we have one side of the triangle missing and we'd look for it first.
Let's side AC = c
AB = a
BC = b
c²=a² - b²
C² = 9² -5²
C² = 81 - 25
C² = 56
C = √56
For angle at B
√56/sinb = 9/sin90
Sin 90 = 1
Sinb = √56/9
b = sin^-1 (√56/9)
b = 56.251°
To the nearest hundredth
b = 56.25°