Question

What are the two solutions of 2x^2 = -x2 – 5x - 1?

Answer 1

Explanation:

Let's solve your equation step-by-step.

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`2x^2=-x^2-5x-1`1

Step 1: Subtract -x^2-5x-1 from both sides.

`2x^2-(-x^2-5x-1)=-x^2-5x-1-(x^2-5x-1)`

`3x^2+5x+1=0`

For this equation: a=3, b=5, c=1

`3x^2+5x+1=0`

Step 2: Use quadratic formula with a=3, b=5, c=1.

`x=(-b+√(b^2-4ac) )/(2a)`

`x=(-(5)+√((5)^2-4(3)(1)) )/(2(3))`

`x=(-5+√(13) )/(6)`

`x=(-5)/(6)+(1)/(6)√(13)` or
`x=(-5)/(6)+(-1)/(6)√(13)` This is the answer

I hope to help you :)