Question

when a body of mass 0.25kg is acted upon by a force, the velocity changes from 5m/s to 7.5m/s. Calculate the work done by the force​

Answer 1

Work done by the force = 1/2m×(v2 - v1)²

m = mass

v2 = final velocity

v1 = initial velocity

= 1/2(0.25)(7.5-5)²

= 1/2(0.25)(2.5)²

= 1/2(0.25)(6.25)

= 0.78J

Hope this helps.